Questions
The refractive index of a lens material is 1.5 and focal length
detailed solution
Correct option is D
1f=(μ−1) 1R1-1R2 1f∝(μ−1) μ'=μ+2%μ=1.02μ=1.02×1.5=1.53 f'f=(μ−1)(μ'−1) f'f-1=(μ−1)(μ'−1)-1 f'-ff×100=(μ−1)-(μ'−1)(μ'−1)×100 =(μ−μ')(μ'−1)×100 =(1.5−1.53)(1.53−1)×100=-5.67%Talk to our academic expert!
Similar Questions
A plano convex lens fits exactly into a plano concave lens. Their plane surfaces are parallel to each other. If lenses are made of different materials of refractive indices and and R is the radius of curvature of the curved surface of the lenses, then the focal length of the combination is
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