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The refractive index of a lens material is 1.5 and focal length f.  Due to some chemical changes in the material, its refractive index has increased by 2%.  The percentage change in its focal length is

a
+45%
b
−45%
c
+5.67%
d
−8%

detailed solution

Correct option is D

μ1=103100×1.5=1.545 f'f=μ-1μ'-1=1.5-11.545-1=0.92 f'f-1100=0.92-1100 f%=-8%

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