Questions
Refractive index of the material of a prism is and refracting angle of the prism is . Then the minimum deviation is
detailed solution
Correct option is D
sin(δm+A2)=μsin(A2)⇒sin(δm+60o2)=3sin30o=32∴ δm+60o2=60o→δm=60oTalk to our academic expert!
Similar Questions
ABC is an isosceles right angled triangle with the angle BAC 90o. A ray of light parallel to the base BC strikes the face AB. The refracted ray in the prism strikes the base BC. If the refractive index of the material of the prism is , find the total angle of deviation of the final emergent ray
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
