First slide

Prism

Question

The refractive index of a prism for a monochromatic wave is $\sqrt{2}$ and its refracting angle is 60°. For minimum deviation, the angle of incidence will be

Moderate

A

30°
B

45°
C

60°
D

75°

Solution

$μ = \frac{sini}{sinA / 2} \Rightarrow \sqrt{2} = \frac{sini}{\sin (\frac{60}{2})} \Rightarrow \sqrt{2} \times \sin 30 = sini \Rightarrow i = 45^{\circ}$

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