First slide

Refrigerator

Question

A refrigerator absorbs 2000 cals of heat from ice trays. If the coefficient of performance is 4, then work done by the motor is

Easy

A

4200 J
B

2100 J
C

8400 J
D

500 J

Solution

coefficient of performance is $β = \frac{Q_{2}}{Q_{1 -} Q_{2}} = \frac{Q_{2}}{W}$
here $Q_{2}$ is 2000 cal and $β = 4$ so W= 500 cal = 2100 J

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