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Questions  

A refrigerator with coefficient of performance 13releases 200 J of heat to a hot reservoir. Then the work done on the working substance is

a
1003J
b
100 J
c
2003J
d
150 J

detailed solution

Correct option is D

The coefficient of performance of a refrigerator is given by β=Q2W=Q2Q1−Q2Substituting the given values, we get    13=Q2200−Q2 or 200−Q2=3Q2or  4Q2=200 or Q2=2004J=50J∴  W=Q1−Q2=200J−50J=150J

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