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A refrigerator with coefficient of performance 1/3 releases 200 J of heat to a hot reservoir, then the work done on the working substance is
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Correct option is D
Coefficient of performanceβ=Q2Q1−Q2=133Q2=Q1−Q24Q2=Q1=200Q2=50W=Q1−Q2=200−50=150JTalk to our academic expert!
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Coefficients of Performance of refrigerator and efficiency if it is working as a Carnot engine are and and according to given figure then correct option.
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