First slide

Refrigerator

Question

A refrigerator with coefficient of performance 1/3 releases 200 J of heat to a hot reservoir, then the work done on the working substance is

Easy

A

$\frac{100}{3} Joule$
B

100 Joule
C

$\frac{200}{3} Joule$
D

150 Joule

Solution

Coefficient of performance
$β = \frac{Q_{2}}{Q_{1} - Q_{2}} = \frac{1}{3}$
$3 Q_{2} = Q_{1} - Q_{2}$
$4 Q_{2} = Q_{1} = 200$
$Q_{2} = 50$
$W = Q_{1} - Q_{2} = 200 - 50 = 150 J$

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