Questions
A refrigerator works between . It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is
detailed solution
Correct option is C
β = Q2W = T2T1-T2(where Q2 is heat removed)⇒600×4.2W = 277303-277⇒ W = 236.5 joule⇒ Power = Wt = 236.5 joule1 sec= 236.5 WTalk to our academic expert!
Similar Questions
For which combination of working temperatures of source and sink, the efficiency of Carnot's heat engine is maximum?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests