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Q.

A refrigerator works between40C and 300C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is (Take 1 cal = 4.2 Joules)

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a

236.5 W

b

2365 W

c

2.365 W

d

23.65 W

answer is A.

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Detailed Solution

Given, T2=4°C=277 K, T1=30°C=303 KQ2=600 cal per second  Coefficient of performance, α=T2T1-T2=277303-277=27726. Also, α=Q2W∴ Work to be done per second = power required =W=Q2α=26277×600 cal per second =26277×600×4.2 J per second =236.5 W
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