First slide

Refrigerator

Question

A refrigerator works between 4^oC and 30^oC. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is : (Take 1 cal : 4.2 joules)

Moderate

A

2.365 W
B

23.65 W
C

236.5 W
D

2365 W

Solution

$β = \frac{Q_{2}}{W} = \frac{T_{2}}{T_{1} - T_{2}} (where Q_{2} is heat removed) \Rightarrow \frac{600 \times 4.2}{W} = \frac{277}{303 - 277} \Rightarrow W = 236.5 joule \Rightarrow Power = \frac{W}{t} = \frac{236.5 joule}{1 \sec} = 236.5 watt .$

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