In a region, electric field depends on X-axis as E = E0x2. There is a cube of edge a as shown. Then find the charge enclosed in that cube.
5ε0 a4 E0
3ε0 a4 E0
4ε0 a4 E0
Zero
E = E0x2 ; Electric field varies from 2a to 3a
Hence E0x22a3ads=qε0
E03a2-E02a2.a2=qε0 5a4E0=qε0⇒q=5ε0a4E0