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Q.

In a region, electric field depends on X-axis as E = E0x2. There is a cube of edge a as shown. Then find the charge enclosed in that cube.

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a

5ε0 a4 E0

b

3ε0 a4 E0

c

4ε0 a4 E0

d

Zero

answer is A.

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Detailed Solution

E = E0x2 ; Electric field varies from 2a to 3aHence E0x22a3ads=qε0E03a2-E02a2.a2=qε0 5a4E0=qε0⇒q=5ε0a4E0
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