Q.

In a region an electric field of 3.2×105 Vm−1 and a magnetic field of 2.0×10−3 Wbm−2 exists perpendicular to each other. An electron in this region travelling perpendicular to both the field does not experiences any deflection. If the electric field is removed, then the electron will revolve in an orbit of radius

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a

45 m

b

4.5 m

c

0.45 m

d

0.045 m

answer is C.

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Detailed Solution

Assuming v as the velocity of electron, E as the Electric field, B as the magnetic field and q as the charge of electron when it goes deflected⇒qE=qvB⇒v=EB⇒v=3.2×1052×10−3=1.6×108m/salsoR=mvqB⇒R=9.1×10−31×1.6×1081.6×10−19×2×10−3=0.45 m
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