In a region of free space, the electric field at some instant of time is E→$$=(80i^+32j^$$−$$64k^)Vm$$ and the magnetic field is B→$$=(0.2i^+0.08j^$$−$$0.29k^)$$μT. The pointing vector for these fields is

Correct option is 411.52i^−28.8j^

Questions

In a region of free space, the electric field at some instant of time is $\vec{E} = (80 \hat{i} + 32 \hat{j} - 64 \hat{k}) \frac{V}{m}$ and the magnetic field is $\vec{B} = (0 .2 \hat{i} + 0 .08 \hat{j} - 0 .29 \hat{k}) μT$ . The pointing vector for these fields is

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−11.52i^+28.8j^

−28.8i^+11.52j^

28.8i^−11.52j^

11.52i^−28.8j^

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detailed solution

Correct option is D

The pointing vector S→=1μ0(E→×B→)

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In a region of free space, the electric field at some instant of time is E→=(80i^+32j^−64k^)Vm and the magnetic field is B→=(0.2i^+0.08j^−0.29k^)μT. The pointing vector for these fields is

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In a region of free space, the electric field at some instant of time is $\vec{E} = (80 \hat{i} + 32 \hat{j} - 64 \hat{k}) \frac{V}{m}$ and the magnetic field is $\vec{B} = (0 .2 \hat{i} + 0 .08 \hat{j} - 0 .29 \hat{k}) μT$ . The pointing vector for these fields is