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Q.

In a region, the intensity of an electric field is given by E=2i^+3j^+k^ in NC−1. The electric flux through a surface S=10i^m2 in the region is:

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a

5 Nm2C-1

b

10 Nm2C-1

c

15 Nm2C-1

d

20 Nm2C-1

answer is D.

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Detailed Solution

Given, E=(2k^+3j^+k^)NC−1 and S=10i^m2We know that,Electric flux,ϕ=E⋅S=(2i^+3j^+k^)⋅(10i^)=20Nm2C−1
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