In a region, the potential is represented by V(x, y, z) = 6x - 8x - 8y + 6yz, where V is in volts and x, y, z are in metres. The electric force experienced by a charge of 2 coulomb situated at point (1, 1, 1) is

Here, V(x,y,z)=6x-8xy-8y+6yz The x,y and z components of electric field E→ are Ex=-∂V∂x=-∂∂x(6x-8xy-8y+6yz)=-(6-8 y)=-6+8 yEy=-∂V∂y=-∂∂y(6x-8xy-8y+6yz)=-(-8 x-8+6 z)=8 x+8-6 zEz=-∂V∂z=-∂∂z(6x-8xy-8y+6yz)=-6y∴  E→=Exi^+Eyj^+Ezk^=(-6+8y)i^+(8x+8-6z)j^-6yk^At point (1, 1, 1)E→=(-6+8)i^+(8+8-6)j^-6k^=2i^+10j^-6k^ The magnitude of electric field E→ is |E→|=Ex2+Ey2+Ez2=(2)2+(10)2+(-6)2=140=235 NC-1Electric force experience by the chargeF=qE=2C×235 NC-1=435 N