In a region of space both electric and magnetic fields exist. A charge particle is fired in that field and it passes unaccelerated. Then
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a
E→ and B→ are parallel
b
E→ and B→ are mutually perpendicular
c
E→ and B→ are mutually perpendicular and velocity of projection V→ must be perpendicular to both E→ and B→ and B = EV
d
If velocity of projection is V→ then E→, B→ and V→must be mutually perpendicular and E = BV
answer is D.
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Detailed Solution
Lorentz force F→ =QV→×B→ + QE→Since acceleration is zero,QV→×B→ + QE→=0⇒E→=B→×V→From the equation it is evident that E→, B→ and V→ are mutually perpendicular.