In a region of space, the electric field is in the x-direction, proportional to x and given by E→=αxi^, where α is a positive constant. Consider an imaginary cubical volume of edge a, with its edges parallel to the axes of coordinates. The charge inside this cubical volume is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
ε0αa3
b
αa3ε0
c
16ε0αa2
d
zero
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The field at the face ABCD =αx0i^So, flux over the face ABCD =−αx0a2 The negative sign arises as the field is directed into the cube The field at the face EFGH=αx0+ai^So, flux over the face EFGH =αx0+aa2The flux over the other four faces is zero as the field is parallel to the surfacesSo, total flux over the cube =αa3=qε0 here q is the total charge inside the cube⇒ q=ε0αa3