The relation between the displacement X of an object produced by the application of the variable force F is represented by a graph shown in the figure. If the object undergoes a displacement from X = 0.5 m to X = 2.5 m the work done will be approximately equal to
Work done = Area under curve and displacement axis
= Area of trapezium
= ×(sum of two parallel lines) × distance between them
=
= = 14 J
As the area actually is not trapezium so work done will be more than 14 J i.e. approximately 16 J