First slide
Work
Question

The relation between the displacement X of an object produced by the application of the variable force F is represented by a graph shown in the figure. If the object undergoes a displacement from X = 0.5 m to X = 2.5 m the work done will be approximately equal to 

Moderate
Solution

Work done = Area under curve and displacement axis
= Area of trapezium
12×(sum of two parallel lines) × distance between them
=  12(10+4)×(2.50.5)
1214×2 = 14 J 
As the area actually is not trapezium so work done will be more than 14 J i.e. approximately 16 J

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App