First slide

Magnetism

Question

The Relation between force between the two poles in free space and medium

Moderate

A

$\frac{F_{m}}{F_{a}} = μ_{r}$
B

$\frac{F_{a}}{F_{m}} = μ_{r}$
C

$\frac{F_{m}}{F_{a}} = μ$
D

$\frac{F_{a}}{F_{m}} = μ$

Solution

Reason & Explanation:
Force between the two poles in free space is $F_{a} = \frac{μ_{o}}{4 π} \frac{m {}_{1}m_{2}}{r^{2}}$ ----------(1)
Force between the two poles in free space is $F_{m} = \frac{μ}{4 π} \frac{m_{1} m_{2}}{r^{2}}$ -----------(2)
(2)/(1) $\Rightarrow$
$\frac{F_{m}}{F_{a}} = \frac{μ}{μ_{0}} = μ_{r}$
Magnetic permeability of free space
$μ \to$ Magnetic permeability of medium
$μ_{r} \to$ Relative permeability of medium

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