Q.

The relation between Internal Energy and Adiabatic constant γ is

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a

U=PVγ−1

b

U=PVγγ−1

c

a & b

d

U=γPV

answer is A.

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Detailed Solution

we know, internal energy dU=nCvdT U2-U1=nCv(T2-T1) if T1=0⇒U1=0    then ⇒U2=nCvT2 ⇒U=nCvT from PV=nRT⇒PVR=nT and Cv=Rγ-1substitute in above equation ⇒U=PVRRγ-1 U=PVγ-1
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