The relation between Internal Energy and Adiabatic constant γ is
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a
U=PVγ−1
b
U=PVγγ−1
c
a & b
d
U=γPV
answer is A.
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Detailed Solution
we know, internal energy dU=nCvdT U2-U1=nCv(T2-T1) if T1=0⇒U1=0 then ⇒U2=nCvT2 ⇒U=nCvT from PV=nRT⇒PVR=nT and Cv=Rγ-1substitute in above equation ⇒U=PVRRγ-1 U=PVγ-1