The relation between the internal energy U and adiabatic constant γ is
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a
U=PVγ−1
b
U=PVγγ−1
c
U=PVγ
d
U=γPV
answer is A.
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Detailed Solution
Change in internal energyΔU=μCvΔT ⇒U2−U1=μCvT2−T1 Let initially T1=0 so U1=0 and finally T2=T and U2=UU=μCvT=μT×Cv=PVR×Rγ−1=PVγ−1 (As PV=μRT,∴μT=PV/R and Cv=R/(γ−1)