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Q.

The relation between the internal energy U and adiabatic constant γ is

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a

U=PVγ−1

b

U=PVγγ−1

c

U=PVγ

d

U=γPV

answer is A.

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Detailed Solution

Change in internal energyΔU=μCvΔT ⇒U2−U1=μCvT2−T1 Let initially T1=0 so U1=0 and finally T2=T and U2=UU=μCvT=μT×Cv=PVR×Rγ−1=PVγ−1 (As PV=μRT,∴μT=PV/R  and Cv=R/(γ−1)
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