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The relation between time and displacement for two particles is given by
$y_{1} = 0 .06 \sin 2 π (1 .04 t + φ_{1}), y_{2} = 0 .03 \sin 2 π (1 .04 t + φ_{2})$
The ratio of the intensity of the waves produced by the vibrations of the two particles will be

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detailed solution

Correct option is C

I1I2=a12a22=0.060.032=41

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The relation between time and displacement for two particles is given byy1=0.06sin2π(1.04t+φ1), y2=0.03sin2π(1.04t+φ2) The ratio of the intensity of the waves produced by the vibrations of the two particles will be

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Ready to Test Your Skills?

free study material

The relation between time and displacement for two particles is given by
$y_{1} = 0 .06 \sin 2 π (1 .04 t + φ_{1}), y_{2} = 0 .03 \sin 2 π (1 .04 t + φ_{2})$
The ratio of the intensity of the waves produced by the vibrations of the two particles will be