The relation between time ‘t’ and distance x for a moving particle is t=αx2+βx where α and β are constants, If v is the velocity at distance x, then the retardation of the particle is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
2αv3
b
2βv
c
2αβv3
d
2β2v3
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
given relation time is t=αx2+βx differentiate w.r.t. displacement x dtdx=2αx+βvelocity=v=dxdt=12αx+β---(1)∴v=2αx+β−1differentiate w.r.t. x dvdx=−12αx+β−2(2α)substitute equation (1)dvdx=−2α2αx+β2=−2αv2 we know,a=v.dvdx since a=dvdt=dvdtdxdx=dxdtdvdx=vdvdx a=−2αv3 retardation of the paticle=2αv3