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Questions  

In the relation V=π8Pr4nl, where the letters have their usual meanings, the dimensions of V are 

a
M0L3T0
b
M0L3T−1
c
M0L−3T−1
d
M1L3T0

detailed solution

Correct option is B

V=π8Pr4nl=ML−1T−2L4ML−1T−1L=M0L3T−1

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