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Questions  

In the relation v=π8Pr4nl,  where the letters have their usual meanings, the dimensions of v are

a
M0L3T0
b
M0L3T−1
c
M0L−3T−1
d
M1L3T0

detailed solution

Correct option is B

V=π8Pr4nl=(ML−1T−2)L4(ML−1T−1)L=M0L3T−1

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