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In the relation $y = r \sin (ω t - k x),$ the dimensional formula of $ω / k$ are

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Correct option is B

Given, y=rsinωt-kxwhere, ωt=angle∴ ω=1T=T-1 angle is dimensionlessSimilarly kx = angle∴ k=1x=L-1ωk=T-1L-1=LT-1

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In the relation y=rsinωt-kx, the dimensional formula of ω/k are

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In the relation $y = r \sin (ω t - k x),$ the dimensional formula of $ω / k$ are