Q.

In the relation y=rsin⁡(ωt−kx), the dimensions of ω/k are

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a

M0L0T0

b

M0L1T−1

c

M0L0T1

d

M0L1T0

answer is B.

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Detailed Solution

y=rsin⁡(ωt−kx) Here ωt= angle ⇒ω=1T=T−1 Similarly, kx= angle ⇒k=1x=L−1 ∴ ωk=T−1L−1=LT−1Or simply ω/k represents wave velocity.ωk=2πf2π/λ=fλ=v, where f is frequency.
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In the relation y=rsin⁡(ωt−kx), the dimensions of ω/k are