The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is (5.00$$±$$0.05) Newton and weight in water is (4.00$$±$$0.05) Newton. Then the relative density along with the maximum permissible percentage error is

Question

Infinity Learn · Accepted Answer

Weight in $$air=(5.00$$±$$0.05)NWeight$$ in water $$=(4.00$$±$$0.05)NLoss$$ of weight in water $$=(1.00$$±$$0.1)NNow$$ relative density $$=$$ weight in air  weight loss in water R.$$D=5.00$$±$$0.051.00$$±$$0.1Now$$ relative density with max permissible errorMean Value of $$RD=5.001.00=5.0$$ Percentage error in $$RD=0.055.00+0.11.00$$×$$100=11$$% ∴$$RD=5.0$$±$$11$$%

The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is (5.00 $\pm$ 0.05) Newton and weight in water is (4.00 $\pm$ 0.05) Newton. Then the relative density along with the maximum permissible percentage error is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is (5.00±0.05) Newton and weight in water is (4.00±0.05) Newton. Then the relative density along with the maximum permissible percentage error is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The relative density of material of a body is found by weighing it first in air and then in water. If the weight in air is (5.00 $\pm$ 0.05) Newton and weight in water is (4.00 $\pm$ 0.05) Newton. Then the relative density along with the maximum permissible percentage error is