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The relative density of a metal may be found by hanging a block of the metal from a spring balance and noting that in air the balance reads ( 5.00 $\pm$ 0.05) N while in water it reads ( 4.00 $\pm$ 0.05)N. The relative density would be quoted as:

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( 5.00 ± 0.05)

5.00 ± 11%

( 500 ± 0.10)

5.00 ± 6%

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detailed solution

Correct option is B

RD=W1W1-W2=55-4=5 loss of wt=W1-W2=5-4±0.05+0.05=1±0.1 Δρρ×100=0.055+0.11.00×100=11%

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The relative density of a metal may be found by hanging a block of the metal from a spring balance and noting that in air the balance reads ( 5.00 ± 0.05) N while in water it reads ( 4.00 ± 0.05)N. The relative density would be quoted as:

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Ready to Test Your Skills?

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The relative density of a metal may be found by hanging a block of the metal from a spring balance and noting that in air the balance reads ( 5.00 $\pm$ 0.05) N while in water it reads ( 4.00 $\pm$ 0.05)N. The relative density would be quoted as: