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Q.

The relative density of a substance may be found by weighing it first in air and then in water. If its weight in air is 6±0.06N and weight in water is 3±0.04N, then the relative density along with permissible error will be given as

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a

2±4.3%

b

2±11%

c

2±4%

d

6±4%

answer is A.

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Detailed Solution

If R be the relative density, then R=WairWair - Water=6±0.063±0.1=61±0.0131±0.033⇒R=21±0.011±0.033−1=21±0.011∓0.033=21±0.043∴ R=2 and ΔR=2×0.043⇒ΔRR=0.043∴ R=2±4.3%

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