First slide

Inductance

Question

Relative position of two coils 1 and 2 is fixed. Coil 1 is carrying no current and when the current in coil 2 is increasing at a constant rate of 10 A/S, the emf induced in coil 1 is 20 mV. Find the magnetic flux linked with coil 2, which is not carrying any current, when coil 1 is carrying a current of 10 A.

Easy

A

0.05 W
B

0.58 W
C

0.24 W
D

0.02 W

Solution

If M be the coefficient of mutual inductance then $ε_{12} = - M \frac{d l_{2}}{d t} \Rightarrow 20 \times 10^{- 3} = M \times 10 \Rightarrow M = 2 \times 10^{- 3} H$
$∴ ϕ_{21} = M i_{1} = 2 \times 10^{- 3} \times 10 weber = 0.02 weber$

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