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Questions  

Resistance of 100 cm long potentiometer wire is 10  Ω.  It is connected to a battery (2 volt) and a resistance R in series. A source of 10 mV gives null point at 40 cm length, then external resistance R is

a
490  Ω
b
790  Ω
c
590  Ω
d
990  Ω

detailed solution

Correct option is B

E =  eR+Rh+r RL×  l 10 × 10−3=  210+R+0 ×  101× 0.4⇒R=790 Ω

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