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Q.

Resistance of 100 cm long potentiometer wire is 10  Ω.  It is connected to a battery (2 volt) and a resistance R in series. A source of 10 mV gives null point at 40 cm length, then external resistance R is

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a

490  Ω

b

790  Ω

c

590  Ω

d

990  Ω

answer is B.

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Detailed Solution

E =  eR+Rh+r RL×  l 10 × 10−3=  210+R+0 ×  101× 0.4⇒R=790 Ω
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