Q.
A resistance of 20Ω is connected to a source of an alternating potentialV=220 sin100πt . The time taken by the current to change from the peak value to rms value, is
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
0.2 s
b
0.25 s
c
2×10-3s
d
2.5×10-3s
answer is D.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
Both V and I are in the same phase. So, let us calculate the time taken by the voltage to change from peak value to rms value. Now 220=220 sin100πt1or 100πt1=π2 or t1=1200sAgain, 2202=220 sin 100πt1or 12=sin 100πt2 or 100πt2=3π4or t2=3400sRequired time =t2-t1=1400s=2.5×10-3s
Watch 3-min video & get full concept clarity