A resistance of $$20$$Ω is connected to a source of an alternating $$potentialV=220$$ $$sin100$$$$π$$t . The time taken by the current to change from the peak value to rms value, is

Question

A resistance of $$20$$Ω is connected to a source of an alternating $$potentialV=220$$ $$sin100$$$$π$$t . The time taken by the current to change from the peak value to rms value, is

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Both V and I are in the same phase. So, let us calculate the time taken by the voltage to change from peak value to rms value. Now $$220=220$$ $$sin100$$$$π$$$$t1or$$ $$100$$$$π$$$$t1=$$π$$2$$ or $$t1=1200sAgain$$, $$2202=220$$ $$sin$$ $$100$$$$π$$$$t1or$$ $$12=$$$$sin$$ $$100$$$$π$$$$t2$$  or  $$100$$$$π$$$$t2=3$$$$π$$$$4or$$  $$t2=3400sRequired$$ time $$=t2-t1=1400s=2.5$$×$$10-3s$$

A resistance of $20 Ω$ is connected to a source of an alternating potential $V = 220 \sin (100 π t)$ . The time taken by the current to change from the peak value to rms value, is

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A resistance of 20Ω is connected to a source of an alternating potentialV=220 sin100πt . The time taken by the current to change from the peak value to rms value, is

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A resistance of $20 Ω$ is connected to a source of an alternating potential $V = 220 \sin (100 π t)$ . The time taken by the current to change from the peak value to rms value, is