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Q.

Resistance of a galvanometer coil is 100Ω and permissible current through its coil is 10 mA. If can be converted into an ammeter of range 1A by connecting a resistance of

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a

1.9 Ω

b

2.1 Ω

c

0.9 Ω

d

1.01 Ω

answer is D.

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Detailed Solution

The resistance R is to be connected in parallel combination with the galvanometer coil.∴ R1−10×10−3=100×10×10−3⇒R=1000×10−31−0.01Ω=1.01Ω
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