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Questions  

The resistance of a galvanometer is 50  Ω and the current required to give full scale deflection is 100  μA. In order to convert it into an ammeter, reading upto 10 A, it is necessary to put a resistance of

a
5 ×  10−3 Ω  in  parallel
b
5 ×  10−4 Ω  in  parallel
c
5 ×  10−5 Ω  in series
d
5 ×  10−3 Ω  in  series

detailed solution

Correct option is B

Resistance in parallel, S=Gigi−ig =  50 × 100 × 10−610 − 100 × 10−6⇒   S=5  × 10−4 Ω

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