Resistance of a galvanometer is 20 Ω. A shunt resistance R is connected to the galvanometer coil to convert galvanometer into an ammeter. If 5% of main current passes through the galvanometer, value of R is
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answer is 4.
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Detailed Solution
If I be the main current, then R x 95100I=20 x 5I100⇒R=2019 Ω