The resistance of a heater coil is $$110$$ ohm. A resistance R is connected in parallel with it and the combination is joined in series with a resistance of $$11$$ ohm to a $$220$$ volt main line. The heater operates with a power of $$I10$$ watt. The value of R in ohm is

Question

Infinity Learn · Accepted Answer

Power consumed by heater is $$110$$ W, so by usingP $$=$$ $$V2R110$$ $$=$$ $$V2110$$ ⇒ $$V=110V$$. Also from figure, $$i1$$ $$=$$ $$110110$$ $$=$$ $$1A$$ and i $$=$$ $$11011$$ $$=$$ $$10A$$.  So  $$i2$$ $$=10$$−$$1=9AApplying$$ Ohm's law for resistance R, V $$=$$ iR⇒  $$110=9$$  ×  R ⇒ $$=12.22$$  Ω

The resistance of a heater coil is 110 ohm. A resistance R is connected in parallel with it and the combination is joined in series with a resistance of 11 ohm to a 220 volt main line. The heater operates with a power of I10 watt. The value of R in ohm is

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