Questions
The resistance of a moving coil galvanometer is 10 and gives a full scale deflection for a current 5 mA The series resistance required to convert it into a voltmeter to read maximum 100 volt is
detailed solution
Correct option is A
See fig. we know that ig=V(R+G)5×10−3=100R+10Solving, we get R = 19990 ΩTalk to our academic expert!
Similar Questions
A galvanometer, having a resistance of 50 gives a full scale deflection for a current of 0.05 A. The length in metre of a resistance wire of area of cross-section 2.97x 10-2 cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (specific resistance of wire = 5 x 10-7 m)
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