The resistance of a moving coil galvanometer is 10 Ω and gives a full scale deflection for a current 5 mA The series resistance required to convert it into a voltmeter to read maximum 100 volt is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
19,990 Ω
b
19980 Ω
c
20010 Ω
d
20000 Ω
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
See fig. we know that ig=V(R+G)5×10−3=100R+10Solving, we get R = 19990 Ω