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Q.

A resistance of 40 ohm and an inductance of 95.5 millihenry are connected in series in a 50 cycles/second ac circuit. The impedance of this combination is very nearly

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a

30 ohm

b

40 ohm

c

50 ohm

d

60 ohm

answer is C.

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Detailed Solution

Z=R2+(2πνL)2=(40)2+4π2×(50)2×(95.5×10−3)2=50  ohm
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