First slide

AC Circuits

Question

A resistance of 40 ohm and an inductance of 95.5 millihenry are connected in series in a 50 cycles/second ac circuit. The impedance of this combination is very nearly

Moderate

A

30 ohm
B

40 ohm
C

50 ohm
D

60 ohm

Solution

$Z = \sqrt{R^{2} + {(2 πνL)}^{2}}$
$= \sqrt{{(40)}^{2} + 4 π^{2} \times {(50)}^{2} \times {(95 .5 \times 10^{- 3})}^{2}} = 50 ohm$

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