First slide

Phasors and Phasor Diagrams

Question

A resistance of 40 ohm and an inductance of 95.5 millihenry are connected in series in a 50 cycles/second AC circuit. The impedance of this combination is very nearly

Moderate

A

30 ohm
B

40 ohm
C

50 ohm
D

60 ohm

Solution

$Z = \sqrt{R^{2} + (2 πvL)^{2}}$
$= \sqrt{(40)^{2} + 4 π^{2} \times (50)^{2} \times {(95 .5 \times 10^{- 3})}^{2}} = 50 ohm$

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