Temperature and heat-thermal properties of matter

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Question

The resistance of a platinum-resistance thermometer is found to be 11.00 $Ω$ ,when dipped in a triple point cell. When it is dipped in a bath the resistance is found to be 28.887 W ? Find the temperature of bath in °C on platinum scale.

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Solution

In terms of triple point of water
$\begin{array}{l} T_{K} = [273 .16 \frac{R}{R_{tr}}] K \\ So, T_{K} = 273 .16 \times \frac{28 .887}{11 .00} = 717 .32 K \\ Now T_{C} = T_{K} - 273 .15 \\ T_{C} = 717 .32 - 273 .15 = 444 {.17}^{\circ} C \end{array}$

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