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Q.

The resistance of a potentiometer wire of length 200cm is 10Ω . This wire is connected in series with a 20 v battery and an external resistance of 30Ω . What will be the balancing length of a secondary cell of emf 4 volt?

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a

120cm

b

160cm

c

180cm

d

140cm

answer is B.

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Detailed Solution

Current in the potentiometer wire is given by i=2010+30A=0.5APotential gradient =0.5 x 10200v/cm=140v/cmIf x cm be the balancing length, Then140 ×x=4⇒x=160cm

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The resistance of a potentiometer wire of length 200cm is 10Ω . This wire is connected in series with a 20 v battery and an external resistance of 30Ω . What will be the balancing length of a secondary cell of emf 4 volt?