A resistance $$R1$$ is connected in the left gap of a metre bridge and a resistance of $$9$$Ω is connected the right gap in the metre bridge. The null point divides the bridge wire in the ratio $$4$$:$$3$$. Now another resistance x Ω is connected in series with $$R1$$ in the left gap of te metre bridge and this time the null point divides the bridge wire in the ratio $$4$$:$$1$$. Then the value of ‘x’ is

Question

A resistance $$R1$$ is connected in the left gap of a metre bridge and a resistance of $$9$$Ω is connected the right gap in the metre bridge. The null point divides the bridge wire in the ratio $$4$$:$$3$$. Now another resistance x Ω is connected in series with $$R1$$ in the left gap of te metre bridge and this time the null point divides the bridge wire in the ratio $$4$$:$$1$$. Then the value of ‘x’ is

Infinity Learn · Accepted Answer

$$R1R2=43$$.....(1)and$$ $$R1+xR2=41$$.....$$(2)∴ $$R1R2+xR2=4$$⇒$$43+xR2=4$$⇒$$xR2=4$$−$$43$$−$$83$$∴ $$x=83R2=83$$×$$9$$ Ω$$=24$$ Ω

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