Questions
A resistance ‘R’ draws power ‘P’ when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes ‘Z’, the power drawn will be
detailed solution
Correct option is C
P=VrmsIrms=Vrms×VrmsR P=Vrms2R⇒Vrms2=PR . . . . (i) Case II : Power drawn in LR circuit P'=VrmsIrmscosϕ=Vrms×VrmsZ×RZ=Vrms2RZ2=PR×RZ2 (using eqn. (i))P'=PR2Z2Talk to our academic expert!
Similar Questions
An LCR series circuit with a resistance of 100 ohm is connected to an ac source of 200 V (r.m.s.) and angular frequency 300 rad/s. When only the capacitor is removed, the current lags behind the voltage by 60o . When only the inductor is removed the current leads the voltage by 60o . The average power dissipated is
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