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Q.

The resistance R=VI where V=(100±5)voltand I=(10±0.2)amp . Find the percentage error in R

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a

5.2%

b

7%

c

4%

d

2.5%

answer is B.

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Detailed Solution

V=100±5 I=10±0.2R=VI∆RR=∆VV+∆II         = 5100+0.210         = 5100+2100         =  7100∆RR×100=7%
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