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Questions  

The resistance R=VI where V=(100±5)voltand I=(10±0.2)amp . Find the percentage error in R

a
5.2%
b
7%
c
4%
d
2.5%

detailed solution

Correct option is B

V=100±5 I=10±0.2R=VI∆RR=∆VV+∆II         = 5100+0.210         = 5100+2100         =  7100∆RR×100=7%

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