The resistance $$R=VI$$, where $$V=(50$$±$$2)V$$ and $$I=(20$$±$$0.2)A$$. The percentage error in R is ‘x’ %.The value of ‘x’ to the nearest integer is………………

dRR×$$100=dVV$$×$$100+dII$$×$$100$$ $$=250$$×$$100+0.220$$×$$100$$ $$=$$ $$4+1=5$$%

Accuracy; precision of instruments and errors in measurements

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Question

The resistance $R = \frac{V}{I},$ where $V = (50 \pm 2) V a n d I = (20 \pm 0.2) A$ . The percentage error in R is ‘x’ %.The value of ‘x’ to the nearest integer is………………

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Solution

$\frac{d R}{R} \times 100 = \frac{d V}{V} \times 100 + \frac{d I}{I} \times 100 = \frac{2}{50} \times 100 + \frac{0.2}{20} \times 100 = 4 + 1 = 5 %$

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