The resistance $$R=Vi$$ where $$V=100$$± $$5$$ volt and $$i=10$$± $$0.2Amp$$. Then the maximum error in ‘R’ is $$______$$

Base value of $$R=10010=10$$Ω.Now, $$R=Vi$$−$$1$$∴ ΔRR×$$100max$$%$$=$$ΔVV×$$100$$%$$+$$Δii×$$100$$×$$100$$% $$=5100$$×$$100$$%$$+0.210$$×$$100$$%$$=7$$%

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Question

The resistance $R = \frac{V}{i}$ where $V = (100 \pm 5) volt and i = (10 \pm 0 .2) Amp .$ Then the maximum error in ‘R’ is ______

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Solution

$\begin{array}{l} Base value of R = \frac{100}{10} = 10 Ω . \\ Now, R = {Vi}^{- 1} \\ ∴ {(\frac{ΔR}{R} \times 100)}_{\max} % = (\frac{ΔV}{V} \times 100) % + (\frac{Δi}{i} \times 100) \times 100 % \\ = \frac{5}{100} \times 100 % + \frac{0 .2}{10} \times 100 % = 7 % \end{array}$

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