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Q.

The resistance of a semicircle shown in fig. between its two end faces is (Given that radial thickness = 3 cm, axial thickness = 4 cm, inner radius = 6 cm and resistivity = 4×10−6Ωcm)

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a

24.15×10−6Ω

b

7.85×10−7Ω

c

7.85×10−6Ω

d

7.85×10−5Ω

answer is C.

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Detailed Solution

Here, A = 4 cm x 3 cm = 12 cm2I=πr=π(6+3/2)=π×7.5cmR=ρ/A=4×10−6×π×7.512= 7.85x10-6 ohm.
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