Questions
The resistance of the series combination of two resistance is S. When they are joined in parallel the total resistance is P. If S = nP, then the minimum possible value of n is
detailed solution
Correct option is A
If two resistances are R1 and R2, thenS=R1+R2 and P=R1R2R1+R2From given condition, S = nPor R1 + R2=nR1R2R1+R2⇒ R1+R22 = nR1R2 ⇒ R1−R22 + 4R1R2=nR1R2So n=4+R1−R22R1R2. Hence, minimum value of n is 4.Talk to our academic expert!
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