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Questions  

The resistance in the two arms of the meter bridge are 5  Ω  and R  Ω  respectively. When the resistance ‘R’ is  shunted with an equal resistance , the new balance point is at  1.6l1. The resistance ‘R’ is

a
15 Ω
b
20 Ω
c
25 Ω
d
10 Ω

detailed solution

Correct option is A

Initial condition 5l1=R100−l1−−−−(1) Final condition 51.6l1=R2100−1.6l1 R1.6100−l1=R2100−1.6l1−−−−(2)  from equation (1)  1.6100−l1=2100−1.6l1 ⇒160−1.6l1=200−3.2l1 ⇒1.6l1=40 ⇒l1 = 40016 = 25 From equation (1) 525 = R100−25 ⇒ R = 15 Ω

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Similar Questions

In a meter bridge, null point is 20 cm, when the known resistance R is shunted by 10Ω resistance, null point is found to be shifted by 10 cm. Find the unknown resistance X.


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