Questions
The resistance in the two arms of the meter bridge are and respectively. When the resistance ‘R’ is shunted with an equal resistance , the new balance point is at . The resistance ‘R’ is
detailed solution
Correct option is A
Initial condition 5l1=R100−l1−−−−(1) Final condition 51.6l1=R2100−1.6l1 R1.6100−l1=R2100−1.6l1−−−−(2) from equation (1) 1.6100−l1=2100−1.6l1 ⇒160−1.6l1=200−3.2l1 ⇒1.6l1=40 ⇒l1 = 40016 = 25 From equation (1) 525 = R100−25 ⇒ R = 15 ΩTalk to our academic expert!
Similar Questions
In a meter bridge, null point is 20 cm, when the known resistance R is shunted by resistance, null point is found to be shifted by 10 cm. Find the unknown resistance X.
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